English Title
Solution succincta et elegans problematis, quo quaeruntur tres numeri tales, ut tam summae quam differentiae binorum sint quadrata
Enestrom Number
753
Fuss Index
43
Original Language
Latin
Content Summary
The problem, according to Euler: "Let x, y and z be the three numbers being sought, of which the largest is x and the smallest z, and let x=pp+qq and y=2pq, so that x+y=(p+q)2 and x–y = (p–q)2. In the same way, setting x=rr+ss and z=2rs, then x+z=(r+s)2 and x–z=(r–s)2. In addition to these four conditions being satisfied, it must be that rr+ss = pp+qq. Then, two additional conditions must be added, that y+z = 2pq+2rs and y–z = 2pq–2rs must both be squares." Euler gets x=50, y=50, z=14, then x=733025, y=488000, z=418304. Then, characteristically, he proposes a slightly different problem (section 16) and solves it by the same means.
Published as
Journal article
Published Date
1818
Written Date
1780
Original Source Citation
Mémoires de l'académie des sciences de St.-Petersbourg, Volume 6, pp. 54-65.
Opera Omnia Citation
Series 1, Volume 5, pp.20-27.
Record Created
2018-09-25